![]() ![]() If you need the delay to be exact, you can make use of the floating values to the time.sleep() function. Once the above program is executed, the program will be delayed for two seconds, and the next statement will be executed after two seconds. Sleep_time = 2 # delay time added after first print statement In the below example, we have produced a delay of two seconds between the results. Let me explain this with practical examples for clear understanding.Ĭlick Here – Get Prepared for Interviews ! Python time.sleep() function examples: A void is the return value for the Python function. It generally produces a stop in the program for the particular seconds during the program execution. In the above syntax, seconds are the parameter. The syntax using the time.sleep() function is sleep(seconds) You can use the time.sleep() function once after the module is imported. ![]() You need to make use of the following command to make use of the Python function. The time.sleep() function in Python belongs to Python’s time module. It generally provides a delay in executing the programs, it pauses only the running thread and let the remaining program to run. The function joins the Python’s time module. Python time.sleep() function is characterized in both of the Python versions, namely 2 and 3. Sleep functions are one of the critical aspects needed when there is s purpose of stopping the program flow and require the other executions to occur. In this tutorial, we will learn about the Python time Sleep() | time.Sleep() Method in Python in depth. It is made possible through Python’s time.sleep() function. Can’t tell for sure without knowing which MQTT library you are using.In some cases, we need our sections or program to get executed after some period of time. If your MQTT client library is dependent on the current thread being able to continue running, then it may be that your first mqttc.publish call queues the message, but the code that actually sends it to the wire does not run for five seconds which may be more than an internal time out so that message gets tossed, undelivered. However, the way time.sleep works is that it slams the brakes on the current thread for the amount of time you requested. Chances are that time.sleep is in fact “working properly”, in the sense that it most likely is doing exactly what you asked it to do. The one thing that I see as problematic in your code is time.sleep. Without more details, it is hard to pinpoint an issue with any specificity. What is mqttc? Probably an MQTT client but where does it come from? How is it initialized? Which MQTT library you are using for it? Also it might help to know the values of MQTT_QOS and MQTT_RETAIN, as they make a difference in how messages are delivered.Īnd how do you observe what’s been published? Mqttc.publish(MQTT_TOPIC_DEFOUT, payload='Defrost inactive', qos=MQTT_QOS, retain=MQTT_RETAIN) #time.sleep set to 5 seconds for testing purpose Mqttc.publish(MQTT_TOPIC_DEFOUT, payload='Dripoff in progress', qos=MQTT_QOS, retain=MQTT_RETAIN) Mqttc.publish(MQTT_TOPIC_DEFOUT, payload='Defrosting in progress', qos=MQTT_QOS, retain=MQTT_RETAIN)Įlif message.topic = MQTT_TOPIC_DEFROST and message.payload = '0': This is my code: if message.topic = MONITOR_REFRESH:Įlif message.topic = MQTT_TOPIC_DEFROST and message.payload = '1': Im trying to get this to work using time.sleep, however the first message isn’t being sent, and after the set time in time.sleep it sends the second message.Ĭould someone tell me why this is happening? I don’t have very much experience writing Python. I want to send a MQTT message on a input state change, and some time after the input state change send another message to the same topic as the first message. I’m currently developing a cold storage monitoring system using a PiFace which communicates over MQTT. ![]()
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